document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32822>Question 32822</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation.\r<BR>\n" );
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document.write( "1.   3a^2=-a+2\r<BR>\n" );
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document.write( "2.   3(x-3)=2(6-x)\r<BR>\n" );
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document.write( "I am having alot of trouble with these three problems.  I got x=-9 for problem two. I need for somebody to show me the steps so that I can understand them for the test.  These questions do not come from a book they are comming from a review sheet.  I know there is only one submission per day but I really need help on these three problms.  Thanks hope you can help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19235 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.   3a^2=-a+2<BR>\n" );
document.write( "first, let us get the whole equation equal to zero; so:<BR>\n" );
document.write( "3a^2+a-2=0<BR>\n" );
document.write( "then, multiply the leading coefficient(the coefficient with the variable that has the highest degree; it is 3 in this problem) with the constant (the number that doesn't have a variable; it is -2 in this problem) to get -6......<BR>\n" );
document.write( "now, find factors of -6 that add up to the coefficient of the middle term (1a)<BR>\n" );
document.write( "Those factors are 3 and -2....so let us fit those numbers into the problem<BR>\n" );
document.write( "3a^2+a-2=0 original<BR>\n" );
document.write( "3a^2+3a-2a-2=0 original with factors<BR>\n" );
document.write( "(3a^2+3a)+(-2a-2)=0 grouping<BR>\n" );
document.write( "3a(a+1)-2(a+1)=0 take out the common multiple<BR>\n" );
document.write( "(3a-2)(a+1)=0 combine<BR>\n" );
document.write( "now, use the zero property to find what (a) is:<BR>\n" );
document.write( "3a-2=0<BR>\n" );
document.write( "a=2/3<BR>\n" );
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document.write( "a+1=0<BR>\n" );
document.write( "a=-1<BR>\n" );
document.write( "SO, -1 and 2/3 are your answers!<BR>\n" );
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document.write( "2.   3(x-3)=2(6-x)<BR>\n" );
document.write( "3(x-3)=2(6-x) original<BR>\n" );
document.write( "3x-9=12-2x distribute<BR>\n" );
document.write( "5x=21 get all variables to one side and vise versa with constant numbers<BR>\n" );
document.write( "x=21/5 your answer!\r<BR>\n" );
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