document.write( "Question 32822: Solve the equation.\r
\n" ); document.write( "\n" ); document.write( "1. 3a^2=-a+2\r
\n" ); document.write( "\n" ); document.write( "2. 3(x-3)=2(6-x)\r
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\n" ); document.write( "\n" ); document.write( "I am having alot of trouble with these three problems. I got x=-9 for problem two. I need for somebody to show me the steps so that I can understand them for the test. These questions do not come from a book they are comming from a review sheet. I know there is only one submission per day but I really need help on these three problms. Thanks hope you can help.
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Algebra.Com's Answer #19234 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1. 3a^2+a-2=0
\n" ); document.write( "Use the quadratic formula as illustrated below:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aa%5E2%2Bba%2Bc=0\" (in our case \"3a%5E2%2B1a%2B-2+=+0\") has the following solutons:
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\n" ); document.write( " \"a%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A3%2A-2=25\".
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\n" ); document.write( " Discriminant d=25 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+25+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"a%5B1%5D+=+%28-%281%29%2Bsqrt%28+25+%29%29%2F2%5C3+=+0.666666666666667\"
\n" ); document.write( " \"a%5B2%5D+=+%28-%281%29-sqrt%28+25+%29%29%2F2%5C3+=+-1\"
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\n" ); document.write( " Quadratic expression \"3a%5E2%2B1a%2B-2\" can be factored:
\n" ); document.write( " \"3a%5E2%2B1a%2B-2+=+3%28a-0.666666666666667%29%2A%28a--1%29\"
\n" ); document.write( " Again, the answer is: 0.666666666666667, -1.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B1%2Ax%2B-2+%29\"

\n" ); document.write( "\n" ); document.write( "2.You will need to post this with parentheses properly
\n" ); document.write( "placed so we can tell where numerators and denominators
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\n" ); document.write( "3. Expanding the original problem you get the following:
\n" ); document.write( " 3x-9=12-2x
\n" ); document.write( " 3x-2x=12+9
\n" ); document.write( " x = 21
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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