document.write( "Question 32822: Solve the equation.\r
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document.write( "1. 3a^2=-a+2\r
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document.write( "2. 3(x-3)=2(6-x)\r
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document.write( "I am having alot of trouble with these three problems. I got x=-9 for problem two. I need for somebody to show me the steps so that I can understand them for the test. These questions do not come from a book they are comming from a review sheet. I know there is only one submission per day but I really need help on these three problms. Thanks hope you can help. \n" );
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Algebra.Com's Answer #19234 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1. 3a^2+a-2=0 \n" ); document.write( "Use the quadratic formula as illustrated below: \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2.You will need to post this with parentheses properly \n" ); document.write( "placed so we can tell where numerators and denominators \n" ); document.write( "start and end. \n" ); document.write( "3. Expanding the original problem you get the following: \n" ); document.write( " 3x-9=12-2x \n" ); document.write( " 3x-2x=12+9 \n" ); document.write( " x = 21 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |