document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261047>Question 261047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me.... I can't remember the basics for this problem:\r<BR>\n" );
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document.write( "A rectangle's length is 6 meters more than twice its width. The perimeter is 60 meters. Find the length in meters. \r<BR>\n" );
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document.write( "We aren't supposed to SOLVE the equation, just write each system of equation.\r<BR>\n" );
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document.write( "I got: 6+2(w)=60\r<BR>\n" );
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document.write( "is that correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192309 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the width W, then the length is 2W + 6<BR>\n" );
document.write( "The perimeter is therefore 2(W + 2W + 6)<BR>\n" );
document.write( "or 6W + 12<BR>\n" );
document.write( "as it is = 60, then 6W is 48, W  = 8 and length is 22 metres<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "1/2 perimeter is 30<BR>\n" );
document.write( "so width + length is 30<BR>\n" );
document.write( "so 3W + 6 = 30 </SPAN>\n" );
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