document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=261044>Question 261044</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle whose perimeter is 176 feet, has a length that is six feet longer than its width. what is the area of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192304 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let width be W, then length is W + 6<BR>\n" );
document.write( "Perimeter is 2(W + W + 6) = 176<BR>\n" );
document.write( "2W + 6 = 88<BR>\n" );
document.write( "2W = 82<BR>\n" );
document.write( "W = 41, length = 47 feet<BR>\n" );
document.write( "Area is 41 x 47 = 1927 sq feet </SPAN>\n" );
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