document.write( "Question 261029: how to solve for x if 2sin^2x-3sinx=1 \n" ); document.write( "

Algebra.Com's Answer #192298 by Greenfinch(383) $\"\"$ $\"About$

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The expression you give does not gives answers in the ranges -1 to +
\n" ); document.write( "If you change it to the following (by changing the 1 to -)
\n" ); document.write( "2(sin^2 x) - 3 sin x + 1 = 0
\n" ); document.write( "This factorizes to (2sin x - 1 )(sin x - 1 ) = 0
\n" ); document.write( "so sinx = 0.5 or 1
\n" ); document.write( "x = 30, 90, 150 degrees in the range 0 < x < 360
\n" ); document.write( "If you have a -1 instead of +1, the results are (3+-(sqrt 17))/2 which is very messy
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