document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260938>Question 260938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve this system with substitution<BR>\n" );
document.write( "y=3x+1 and x=3y+1\r<BR>\n" );
document.write( "\n" );
document.write( "I don't get it at all and if you could help me out it'd be great:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192244 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192244\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> substitute 3y+1 for x in the first equation<BR>\n" );
document.write( "y=3(3y+1)+1<BR>\n" );
document.write( "now solve for y<BR>\n" );
document.write( "y=9y+3+1<BR>\n" );
document.write( "bring all y's to one side all numbers to the other<BR>\n" );
document.write( "-4=8y<BR>\n" );
document.write( "-4/8=y<BR>\n" );
document.write( "-1/2=y<BR>\n" );
document.write( "plug that into either original equations<BR>\n" );
document.write( "-1/2=3x+1<BR>\n" );
document.write( "-3/2=3x<BR>\n" );
document.write( "-1/2=x<BR>\n" );
document.write( "Yes that is correct<BR>\n" );
document.write( "(-1/2,-1/2) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );