document.write( "Question 32794: y2=16x how du i graph? \n" ); document.write( "
Algebra.Com's Answer #19224 by stanbon(75887) ![]() You can put this solution on YOUR website! x=(1/16)y^2 \n" ); document.write( "The graph is a parabola with vertex at (0.0) opening to the right. \n" ); document.write( "You graph it by plotting points. \n" ); document.write( "For example: If you let x=1 then y^2=16 and y=4 or -4 \n" ); document.write( "If you let x=(25/16) then y^2=25 and y=5 or y=-5 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |