document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32773>Question 32773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each equation for all values of theta. the problem is sin(theta/2)<BR>\n" );
document.write( " plus cosine(theta/2)= sqrt(2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19223 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin(x/2) + cos(x/2)=sqrt(2)<BR>\n" );
document.write( "sqrt[(1-cosx)/2] + sqrt[(1+cosx)/2] = sqrt(2)<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "1/2 + 1/2 +[sqrt(1-cos^2(x))/2]=2<BR>\n" );
document.write( "sqrt[(1-cos^2(x))/2]=1<BR>\n" );
document.write( "Square both sides again to get:<BR>\n" );
document.write( "(1-cos^2(x))/2=1<BR>\n" );
document.write( "1-cos^2(x)=1<BR>\n" );
document.write( "cos^2(x)=0<BR>\n" );
document.write( "cos(x)=0<BR>\n" );
document.write( "x=90 or 270 degrees.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );