document.write( "Question 260931: At a company fish fry, ½ in attendance are employees. Employees’ spouses are 1/3 of the attendance. What is the percentage of the people in attendance who are not employees or employee spouses? \r
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Algebra.Com's Answer #192222 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
e+w+n=1
\n" ); document.write( "1/2+1/3+n=1
\n" ); document.write( "n=1/6\r
\n" ); document.write( "\n" ); document.write( "3/6+2/6=5/6
\n" ); document.write( "1-5/6=1/6
\n" ); document.write( "Caught me again Ed.
\n" ); document.write( "100*1/6=percentage
\n" ); document.write( "However getting the percentage is much easier than the other tutor suggests.
\n" ); document.write( "Just divide 100 by 6 and the result is the percent.
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