document.write( "Question 260931: At a company fish fry, ½ in attendance are employees. Employees’ spouses are 1/3 of the attendance. What is the percentage of the people in attendance who are not employees or employee spouses? \r
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Algebra.Com's Answer #192222 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! e+w+n=1 \n" ); document.write( "1/2+1/3+n=1 \n" ); document.write( "n=1/6\r \n" ); document.write( "\n" ); document.write( "3/6+2/6=5/6 \n" ); document.write( "1-5/6=1/6 \n" ); document.write( "Caught me again Ed. \n" ); document.write( "100*1/6=percentage \n" ); document.write( "However getting the percentage is much easier than the other tutor suggests. \n" ); document.write( "Just divide 100 by 6 and the result is the percent. \n" ); document.write( " \n" ); document.write( " |