document.write( "Question 260817: the perimeter of a rectangle is 280cm the length is 20cm more than the width. what are the demensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #192191 by checkley77(12844)\"\" \"About 
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L=W+20
\n" ); document.write( "2L+2W=280
\n" ); document.write( "2(W+20)+2W=280
\n" ); document.write( "2W+40+2W=280
\n" ); document.write( "4W=280-40
\n" ); document.write( "4W=240
\n" ); document.write( "W=240/4
\n" ); document.write( "W=60 ANS. FOR THE WIDTH.
\n" ); document.write( "L=60+20=80 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*80+2*60=280
\n" ); document.write( "160+120=280
\n" ); document.write( "280=280\r
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