document.write( "Question 260817: the perimeter of a rectangle is 280cm the length is 20cm more than the width. what are the demensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #192191 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+20 \n" ); document.write( "2L+2W=280 \n" ); document.write( "2(W+20)+2W=280 \n" ); document.write( "2W+40+2W=280 \n" ); document.write( "4W=280-40 \n" ); document.write( "4W=240 \n" ); document.write( "W=240/4 \n" ); document.write( "W=60 ANS. FOR THE WIDTH. \n" ); document.write( "L=60+20=80 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*80+2*60=280 \n" ); document.write( "160+120=280 \n" ); document.write( "280=280\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |