document.write( "Question 260821: Use the quadratic formula to solve the equation.\r
\n" ); document.write( "\n" ); document.write( " 2x^2-3x=-10\r
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\n" ); document.write( "\n" ); document.write( " The solution set would be?\r
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\n" ); document.write( "\n" ); document.write( "Thanks so much for your help.
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Algebra.Com's Answer #192187 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
2x^2-3x=-10
\n" ); document.write( "2x^2-3x+10=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "x=(3+-sqrt[-3^2-4*2*10])/2*2
\n" ); document.write( "x=(3+-sqrt[9-80])/4
\n" ); document.write( "x=(3+-sqrt-71)/4
\n" ); document.write( "x=(3+-8.426i)/4
\n" ); document.write( "x=3/4+-8.426i/4
\n" ); document.write( "x=.75+-2.1i ans.\r
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