document.write( "Question 260874: What is the answer of
\n" ); document.write( "2p + 3q =18
\n" ); document.write( "5p - q =11\r
\n" ); document.write( "\n" ); document.write( "Please show each step. I am having trouble understanding each individual steps.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #192153 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
Here is the original system:
\n" ); document.write( "(i) \"2p+%2B+3q+=18\"
\n" ); document.write( "(ii) \"5p+-+q+=11\"
\n" ); document.write( "step 1 - I see that q's will be easier to get rid of, so I will multiply (ii) by 3 to get
\n" ); document.write( "(iii) \"15p+-+3q+=+33\"
\n" ); document.write( "step 2 - now, by adding down with (i) and (iii) , the q's are gone and I can solve for p. We get
\n" ); document.write( "(iv) \"17p+=+51\"
\n" ); document.write( "step 3 - divide by 17 to get
\n" ); document.write( "(v) \"p+=+3\"
\n" ); document.write( "step 4- now that we have p, we can substitute 3 for p into any equation. Let's put it into (i) and get
\n" ); document.write( "\"2%2A3+%2B+3q+=+18\"
\n" ); document.write( "we get
\n" ); document.write( "\"6+%2B+3q+=+18\"
\n" ); document.write( "subtract 6 to get
\n" ); document.write( "\"3q+=+12\"
\n" ); document.write( "divide by 3 to get
\n" ); document.write( "\"q+=+4\"
\n" ); document.write( "so our answer is
\n" ); document.write( "p = 3, q = 4.
\n" ); document.write( "
\n" );