document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260829>Question 260829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My homework says \"Show that the number is a rationsl by righting it in a/b form. Then give the multiplication inverse and the additive inverse of the number\" how would you do that?<BR>\n" );
document.write( "1. -4/7<BR>\n" );
document.write( "2. 8 2/5<BR>\n" );
document.write( "3. -1 1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192132 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the product of a number and it's multiplicative inverse is equal to 1.\r<BR>\n" );
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document.write( "see <a  rel=nofollow HREF= \"http://www.mathwords.com/m/multiplicative_inverse_of_a_number.htm\" target = \"_blank\">http://www.mathwords.com/m/multiplicative_inverse_of_a_number.htm</a>\r<BR>\n" );
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document.write( "the sum of a number and it's additive inverse is equal to 0.\r<BR>\n" );
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document.write( "see <a  rel=nofollow HREF= \"http://www.mathwords.com/a/additive_inverse_number.htm\" target = \"_blank\">http://www.mathwords.com/a/additive_inverse_number.htm</a>\r<BR>\n" );
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document.write( "to find the multiplicative inverse of a number, you take it's reciprocal.\r<BR>\n" );
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document.write( "you take it's reciprocal by dividing the number into 1.\r<BR>\n" );
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document.write( "to find the additive inverse of a number, you take it's opposite.\r<BR>\n" );
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document.write( "to find it's opposite, you reverse the sign.\r<BR>\n" );
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document.write( "example:\r<BR>\n" );
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document.write( "multiplicative inverse of 5 is 1/5 because 1/5 * 5 = 1\r<BR>\n" );
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document.write( "additive inverse of 5 is -5 because 5 + (-5) = 0\r<BR>\n" );
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document.write( "problem number 1:\r<BR>\n" );
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document.write( "number is -4/7\r<BR>\n" );
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document.write( "multiplicative inverse is -7/4 because -(4/7) * (-7/4) = 1\r<BR>\n" );
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document.write( "we got that by taking (-4/7) and dividing it into 1 to get:\r<BR>\n" );
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document.write( "1/(-4/7)\r<BR>\n" );
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document.write( "if we multiply numerator and denominator of that expression by 7/7, we get:\r<BR>\n" );
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document.write( "7/-4 = (-7/4)\r<BR>\n" );
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document.write( "additive inverse is 4/7 because -(4/7) + (4/7) = 1\r<BR>\n" );
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document.write( "problem number 2:\r<BR>\n" );
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document.write( "number is 8 + 2/5\r<BR>\n" );
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document.write( "convert this number to an improper fraction to get:\r<BR>\n" );
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document.write( "40/5 + 2/5 = 42/5\r<BR>\n" );
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document.write( "multiplicative inverse is 5/42 because 5/42 * 42/5 = 1\r<BR>\n" );
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document.write( "additive inverse is -42/5 because 42/5 + (-42/5) = 0\r<BR>\n" );
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document.write( "problem number 3:\r<BR>\n" );
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document.write( "-1 1/2 is the same as -1 - 1/2.\r<BR>\n" );
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document.write( "convert to improper fraction to get:\r<BR>\n" );
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document.write( "-2/2 - 1/2 = -3/2\r<BR>\n" );
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document.write( "multiplicative inverse is -2/3 because -(3/2) * (-(2/3) = 1\r<BR>\n" );
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document.write( "additive inverse is 2/3 because -2/3 + 2/3 = 0\r<BR>\n" );
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document.write( "note:\r<BR>\n" );
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document.write( "improper fraction is a fraction in a/b form where the numerator is greater than the denominator.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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