document.write( "Question 260820: I need to factor 25w^2 - 121 completely. \r
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\n" ); document.write( "\n" ); document.write( "Thanks so much for your help.\r
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Algebra.Com's Answer #192118 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
set 25w^2 - 121 = 0 to find the roots.\r
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\n" ); document.write( "\n" ); document.write( "add 121 to both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "25w^2 = 121\r
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\n" ); document.write( "\n" ); document.write( "divide both sides by 25 to get:\r
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\n" ); document.write( "\n" ); document.write( "w^2 = 121/25\r
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\n" ); document.write( "\n" ); document.write( "take the square root of both sides to get:\r
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\n" ); document.write( "\n" ); document.write( "w = +/- sqrt(121)/sqrt(25)\r
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\n" ); document.write( "\n" ); document.write( "sqrt(121) = 11
\n" ); document.write( "sqrt(25) = 5\r
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\n" ); document.write( "\n" ); document.write( "equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "w = +/- 11/5\r
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\n" ); document.write( "\n" ); document.write( "graph of this equation looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-5%2C5%2C-150%2C150%2C25%2Ax%5E2-121%29\"\r
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\n" ); document.write( "\n" ); document.write( "you can see that y = 0 when x = +/- 11/5 which is equivalent to +/- 2.2\r
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\n" ); document.write( "\n" ); document.write( "note:\r
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\n" ); document.write( "\n" ); document.write( "to graph the equation, I substituted x for w to satisfy the graphing software requirements.\r
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