document.write( "Question 260813: You need to choose between two telephone plans for local calls. Plan A charges $25 per month for unlimited calls. Plan B has a monthly fee of $13 with a charge of $0.06 per local call. How many local telephone calls in a month make Plan A the better deal?\r
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document.write( "I know that I am supposed to use the greater than and less than signs. Please help!!\r
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document.write( "Thank You!!!! \n" );
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Algebra.Com's Answer #192115 by Theo(13342)![]() ![]() You can put this solution on YOUR website! Plan A charges $25 per month for unlimited calls. \n" ); document.write( "Plan B charges $13 per month plus $.06 per call.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You want to know when plan A costs less than plan B.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set up an equation as follows:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cost for Plan A = $25.00\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Cost for Plan B = $13.00 + .06 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = number of calls per month.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you want to know when plan A Costs are smaller than plan B costs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plan A Costs < Plan B costs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25 < 13 + .06 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 13 from both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25 - 13 < .06 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "12 < .06 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by .06 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "12/.06 < x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "200 < x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is the same as:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x > 200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plan A at $25.00 per month will be cheaper when the number of minutes used per month is > 200.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "200 should be the break even point.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "200 * .06 + 13 = 12 + 13 = 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when the minutes go above 200, plan A at $25 per month will be cheaper.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at 201 minutes, plan B costs .06 * 201 = $12.06 + $13.00 = $25.06 which is more expensive than plan A.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |