document.write( "Question 32691: 4y
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\n" ); document.write( "\n" ); document.write( "12y+6
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Algebra.Com's Answer #19211 by benni1013(206)\"\" \"About 
You can put this solution on YOUR website!
4y/8y+4*12y+6/7==>4y/2(4y+1)*6(2y+1)/7==>4y/4y+1*3(2y+1)/7==>4y(3)(2y+1)/7(4y+1)
\n" ); document.write( "12y(2y+1)/7(4y+1)==>24y^2+12y/28y+7==>12y(2y+1)/7(4y+1
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