document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260757>Question 260757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perpendicular Lines: Write the equation of the line through (4,5) and perpendicular to the line with equation 3x + 2y = -1.\r<BR>\n" );
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document.write( "Please explain how the equation came out to y = 2/3 x + 7 as shown in my example answer key.\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Melissa </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192109 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Glad you provided the answer you have.<BR>\n" );
document.write( "First we have to find the slope of the given line<BR>\n" );
document.write( "3x+2y=-1<BR>\n" );
document.write( "Get y by itself<BR>\n" );
document.write( "2y=-3x-1<BR>\n" );
document.write( "y=-3x/2-1/2<BR>\n" );
document.write( "The slope is -3/2<BR>\n" );
document.write( "So the perpendicular line has to have a slope of 2/3\r<BR>\n" );
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document.write( "2/3*(-3/2)=-1<BR>\n" );
document.write( "The new line goes through (4,5)<BR>\n" );
document.write( "Plug in 4 and 5 to find b<BR>\n" );
document.write( "5=2*4/3+b<BR>\n" );
document.write( "15/3-8/3=b<BR>\n" );
document.write( "7/3=b<BR>\n" );
document.write( "y=2x/3+7/3<BR>\n" );
document.write( "or 3y=2x+7<BR>\n" );
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