document.write( "Question 260766: determine whether the line is PQ is parallel or perpendicular to line with a slope of -2.\r
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Algebra.Com's Answer #192107 by PRMath(133)\"\" \"About 
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determine whether the line is PQ is parallel or perpendicular to line with a slope of -2.\r
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\n" ); document.write( "\n" ); document.write( "Ok, here are two things you have to know:\r
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\n" ); document.write( "\n" ); document.write( "If lines are PARALLEL, they have the SAME slope.
\n" ); document.write( "If lines are PERPENDICULAR, their slopes are negative reciprocals of one another. In other words, if one slope is 2 the negative reciprocal is \"%28-1%29%2F2\". If one slope is -2, then the negative reciprocal is \"1%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "Ok, so you are given that you have a line with a slope of -2. Next you are asked if line PQ is parallel or perpendicular to the line with a slope of -2.\r
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\n" ); document.write( "\n" ); document.write( "Ok, let's just find the slope for line PQ. The way to find slope is to use this formula:\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%5B1%5D+-+y%5B2%5D%29\"/\"%28x%5B1%5D+-+x%5B2%5D%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's plug in the info from PQ\r
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\n" ); document.write( "\n" ); document.write( "\"6+-+8\"/\"5+-+9\" which is
\n" ); document.write( "\"%28-2%29%2F%28-4%29\" which is
\n" ); document.write( "\"2%2F4\" which reduces to
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\n" ); document.write( "The slope of line PQ is: \"1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "The slope we were given was -2. The slope of PQ is \"1%2F2\". Therefore, because \"1%2F2\" is the negative reciprocal of -2, the two lines are PERPENDICULAR.\r
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\n" ); document.write( "\n" ); document.write( "If you get nervous about the use of negative reciprocals, just do one final check. Multiply the first slope times the 2nd. If the answer is -1, then the slopes are indeed negative reciprocals of one another.\r
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\n" ); document.write( "\n" ); document.write( "So let's do that:\r
\n" ); document.write( "\n" ); document.write( "\"%28-2%29%2F1\" x \"1%2F2\" = \"%28-2%29%2F2\" which is \"%28-1%29%2F1\" which is -1.\r
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\n" ); document.write( "\n" ); document.write( "Ok, that's your final check. The lines are perpendicular.\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps you. :-)
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