document.write( "Question 260649: A plane flying the 3020-mile trip from City A to City B has a 60-mph tailwind. The flight's point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. If the speed of the plane in still air is 430 mph, how far from City A is the point of no return? Round your answer to the nearest mile. \n" ); document.write( "
Algebra.Com's Answer #192102 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A plane flying the 3020-mile trip from City A to City B has a 60-mph tailwind. \n" ); document.write( " The flight's point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. \n" ); document.write( " If the speed of the plane in still air is 430 mph, how far from City A is the point of no return? Round your answer to the nearest mile. \n" ); document.write( ": \n" ); document.write( "Let x = distance from city A \n" ); document.write( "Then \n" ); document.write( "(3020-x) = distance from city B \n" ); document.write( ": \n" ); document.write( "Write a time equation: time = dist/speed \n" ); document.write( ": \n" ); document.write( "Continue time = return time \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Cross multiply \n" ); document.write( "490x = 370(3020-x) \n" ); document.write( "490x = 1117400 - 370x \n" ); document.write( "490x + 370x = 1117400 \n" ); document.write( "860x = 1117400 \n" ); document.write( "x = \n" ); document.write( "x = 1299 mi from A is the point of no return \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the times \n" ); document.write( "1299/370 = 3.5 hrs to return to A \n" ); document.write( "(3020-1299)/490 = 3.5 hrs to continue to B\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |