document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260714>Question 260714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If AE = 8x - 3 and EC =6x + 7, then AC = ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192088 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Since we're looking for the length of AC we would add the two smaller lengths like this:<BR>\n" );
document.write( "(8x - 3)+(6x + 7)= combine like terms to be:<BR>\n" );
document.write( "14x+4 is the answer. <BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
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document.write( "www.math-unlock.com </SPAN>\n" );
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