document.write( "Question 260676: Hi :o)
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document.write( "Last calculus question if anyone can help???\r
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document.write( "Find derivative of y = (x-1)³(x²-2)²\r
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document.write( "I thought I'd need to use both the product and chain rules, so tried;\r
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document.write( "u=(x-1)³ du^n/dx=3(x-1)²(1)
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document.write( "v=(x²-2)² dv^n/dx=2(x²-2)^1(2x)\r
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document.write( "= {(x-1)³[3(x-1)²(1)]} + {(x²-2)²[2(x²-2)^1(2x)]}
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document.write( "= [(x-1)³3(x-1)²] + [(x²-2)²4x(x²-2)]
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document.write( "= 3(x-1)^5 + 4x(x²-2)^3\r
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document.write( "...does that look right? Can I go further?
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document.write( "Thanks so, so much again :o) \n" );
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Algebra.Com's Answer #192072 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's confirmation of the answer. \n" ); document.write( " |