document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260721>Question 260721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are 9 members on a board of directors. If they must form a subcommittee of 5 members, how many different subcommittees are possible? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192060 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 chosen from 9 gives the number of combinations as,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=N=9%21%2F%285%21%289-5%21%29%29=9%2A8%2A7%2A6%2F%284%2A3%2A2%29=126 ALIGN=MIDDLE  ALT=\"N=9%21%2F%285%21%289-5%21%29%29=9%2A8%2A7%2A6%2F%284%2A3%2A2%29=126\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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