document.write( "Question 260701: What quantity x of a 75% acid solution must be mixed with a 25% solution to produce 500 mL of a 40% solution?\r
\n" ); document.write( "\n" ); document.write( "Amount x=
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Algebra.Com's Answer #192037 by Fombitz(32388)\"\" \"About 
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x-Amount of 75% solution
\n" ); document.write( "y-Amount of 25% solution
\n" ); document.write( "1.\"x%2By=500\"
\n" ); document.write( "2.\"75x%2B25y=40%28500%29=2000\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"x=500-y\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"75x%2B25y=2000\"
\n" ); document.write( "\"75%28500-y%29%2B25y=20000\"
\n" ); document.write( "\"37500-75y%2B25y=20000\"
\n" ); document.write( "\"-50y=-17500\"
\n" ); document.write( "\"y=350\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"x=500-y\"
\n" ); document.write( "\"x=500-350\"
\n" ); document.write( "\"x=150\"
\n" ); document.write( "Use 150ml of 75% solution and 350ml of 25% solution.
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