document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260702>Question 260702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant blends tea that sells for $3.45 a pound with tea that sells for $2.15       a pound to produce 80lb of a mixture that sells for $2.75 a pound\r<BR>\n" );
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document.write( "Then the mixture contains x lb of $3.45/lb tea and y lb of $2.15/lb tea\r<BR>\n" );
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document.write( "        </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #192036 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=192036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a mixture problem. Here is a table based on the above information.<BR>\n" );
document.write( "tea . . . . . . . . . . . . .$/lb . . . .. . . . . . lb . . . . . . . . . . . $<BR>\n" );
document.write( "A . . . . . . . . . . . . . .($3.45) . . . . . . . x . . . . . . . . . . . ($3.45x)<BR>\n" );
document.write( "B . . . . . . . . . . . . . .($2.15) . . . . . . . 80-x . . . . . . . . .$172 - $2.15x<BR>\n" );
document.write( "mixture . . . . . . . . . ($2.75) . . . . . . .80 . . . . . . . . . . .$220<BR>\n" );
document.write( "First, the variables x and y are there to confuse you. You only need x.<BR>\n" );
document.write( "using the third column we get<BR>\n" );
document.write( "(i) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.45x+%2B+172+-+2.15x+=+220 ALIGN=MIDDLE  ALT=\"3.45x+%2B+172+-+2.15x+=+220\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "combine like terms to get<BR>\n" );
document.write( " (ii) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.30x+%2B+172+=+220 ALIGN=MIDDLE  ALT=\"1.30x+%2B+172+=+220\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "subtract 172 to get<BR>\n" );
document.write( "(iii) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.30x+=+48 ALIGN=MIDDLE  ALT=\"1.30x+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "divide to get<BR>\n" );
document.write( "(iv) x = 36.92<BR>\n" );
document.write( "you need ~ 36.92 lb of the $3.45 tea and ~ 43.08 lb of the $2.15 tea.<BR>\n" );
document.write( "these are unusual answers, but they work. </SPAN>\n" );
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