document.write( "Question 260699: What quantity x of a 75% acid solution must be mixed with a 25% solution to produce 500 mL of a 40% solution?\r
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document.write( "Amount x= \n" );
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Algebra.Com's Answer #192028 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! This is a mixture problem. Here is a chart based on the above information: \n" ); document.write( "acids . . . . . . . . % . . . . . . . . . .ml . . . . . . . . . . . . . %ml \n" ); document.write( "75 . . . . . . . . . .75 . . . . . . . . .x . . . . . . . . . . . . . . . .75x \n" ); document.write( "25 . . . . . . . . . .25 . . . . . . . . .500-x . . . . . . . . . . . 12500 - 25x \n" ); document.write( "mixture . . . . . .40 . . . . . . . . .500 . . . . . . . . . . . . . .20000 \n" ); document.write( "using column three, we get \n" ); document.write( "75x + 12500 - 25x = 20000 \n" ); document.write( "combine like terms to get \n" ); document.write( "50x + 12500 = 20000 \n" ); document.write( "subtract 12500 to get \n" ); document.write( "50x = 7500 \n" ); document.write( "divide to get \n" ); document.write( "x = 150 \n" ); document.write( "we need 150 ml of 75% acid. \n" ); document.write( " |