document.write( "Question 260652: A.) HOW MANY WAYS ARE THERE TO PICK TWO CARDS (W/O REPLACEMENT) SO THAT AT LEAST ONE OF THEM IS AN ACE?\r
\n" ); document.write( "\n" ); document.write( "I TRIED, 52!/(52-4)!4!
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Algebra.Com's Answer #192006 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
order is not important so you're dealing with combinations.\r
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\n" ); document.write( "\n" ); document.write( "there are 52 cards in the deck.\r
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\n" ); document.write( "\n" ); document.write( "there are 4 aces in the deck.\r
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\n" ); document.write( "\n" ); document.write( "you are picking 2 cards out of the deck.\r
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\n" ); document.write( "\n" ); document.write( "at least 1 of them needs to be an ace.\r
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\n" ); document.write( "\n" ); document.write( "assuming exactly 1 of them is an ace, then each ace can be paired with exactly 48 other cards in the deck that are not aces.\r
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\n" ); document.write( "\n" ); document.write( "you have 48 cards that can be paired with the ace of spades.
\n" ); document.write( "you have 48 cards that can be paired with the ace of clubs.
\n" ); document.write( "you have 48 cards that can be paired with the ace of hearts.
\n" ); document.write( "you have 48 cards that can be paired with the ace of diamonds.\r
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\n" ); document.write( "\n" ); document.write( "that's a total of 192 possible pairs.\r
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\n" ); document.write( "\n" ); document.write( "you can also have 2 aces in the pair.\r
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\n" ); document.write( "\n" ); document.write( "this can happen in 6 ways.\r
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\n" ); document.write( "\n" ); document.write( "ace of spades with ace of clubs
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\n" ); document.write( "ace of clubs with ace of hearts
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\n" ); document.write( "\n" ); document.write( "add 6 to 192 and you get a total of 198 pairs of cards that include at least 1 ace in them.\r
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\n" ); document.write( "\n" ); document.write( "if you look at this in terms of combinations, here's what you have:\r
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\n" ); document.write( "\n" ); document.write( "possible combinations of 2 aces from 4 aces is:\r
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\n" ); document.write( "\n" ); document.write( "c(4,2) = 4!/(2!*2!) = 6\r
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\n" ); document.write( "\n" ); document.write( "possible combinations of 1 ace and 1 other card is:\r
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\n" ); document.write( "\n" ); document.write( "c(4,1) * c(48,1) = 4 * 48 = 192\r
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\n" ); document.write( "\n" ); document.write( "add these possible combinations up and you get 198 possible combinations of a pair of cards from a deck of 52 cards where at least one of the4 cards is an ace.\r
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\n" ); document.write( "\n" ); document.write( "the total possible combinations of a pair of cards from a deck of 52 cards is equal to:\r
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\n" ); document.write( "\n" ); document.write( "c(52,2) = 52! / (2!*50!) = 1326.\r
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\n" ); document.write( "\n" ); document.write( "the probability that you will draw a pair of cards with at least 1 ace in there is equal to:\r
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\n" ); document.write( "\n" ); document.write( "198/1326 = .149321267\r
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\n" ); document.write( "\n" ); document.write( "this is equal to the number of pairs that have an ace in them divided by the total number of pairs possible.\r
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