document.write( "Question 260639: the product of two consecutive integers is 71 more than their sum.Find the integers. \n" ); document.write( "
Algebra.Com's Answer #192001 by mananth(16946)\"\" \"About 
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the product of two consecutive integers is 71 more than their sum.Find the integers.\r
\n" ); document.write( "\n" ); document.write( "Let the number be x.
\n" ); document.write( "the consequtive number will x+1\r
\n" ); document.write( "\n" ); document.write( "the product of the two numbers = x*(x+1)
\n" ); document.write( "x*(x+1) = x + x+1 +71 ------------- 1 (71 more than the sum of the two numbers)
\n" ); document.write( "x^2+x = 2x+72
\n" ); document.write( "x^2+x-2x-72=0
\n" ); document.write( "x^2-x-72=0
\n" ); document.write( "x^2-9x+8x-72=0
\n" ); document.write( "x(x-9) + 8(x-9) = 0
\n" ); document.write( "(x-9)(x+8)=0\r
\n" ); document.write( "\n" ); document.write( "so x= 9 or -8 \r
\n" ); document.write( "\n" ); document.write( "The value of -8 satisfies the condition in equation 1\r
\n" ); document.write( "\n" ); document.write( "So the numbers are -8 and -7\r
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\n" ); document.write( "\n" ); document.write( "M Ananth------------ mananth@hotmail.com\r
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