document.write( "Question 260645: A ladder is resting against a wall.The top of the ladder touches the wall at a height of 9 feet.Find the length of the ladder if the length is 3 feet more than its distance from the wall. \n" ); document.write( "

Algebra.Com's Answer #191999 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
A ladder is resting against a wall.The top of the ladder touches the wall at a height of 9 feet.Find the length of the ladder if the length is 3 feet more than its distance from the wall. \r
\n" ); document.write( "\n" ); document.write( "Let the distance of the ladder from the wall be x\r
\n" ); document.write( "\n" ); document.write( "The length of the ladder = x+3\r
\n" ); document.write( "\n" ); document.write( "The ladder touches the wall at a vertical height of 9 feet.\r
\n" ); document.write( "\n" ); document.write( "(x+3)^2 = x^2 + 9^2 ( using the pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( "x^2 + 6x+ 9 = x^2 + 81\r
\n" ); document.write( "\n" ); document.write( "x^2- x^2 +6x = 81-9\r
\n" ); document.write( "\n" ); document.write( "6x= 72\r
\n" ); document.write( "\n" ); document.write( "x= 12\r
\n" ); document.write( "\n" ); document.write( "Therefore the length of the ladder will be x+3 = 12 + 3 =15 Answer.\r
\n" ); document.write( "\n" ); document.write( "M Ananth----------- mananth@hotmail.com\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );