document.write( "Question 260520: the length of a rectangle mailing is four centimeters less than twice the width. the perimeter is 40 centimeters. Find the dimensions of the label? \n" ); document.write( "
Algebra.Com's Answer #191994 by mananth(16946)\"\" \"About 
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the length of a rectangle mailing is four centimeters less than twice the width. the perimeter is 40 centimeters. Find the dimensions of the label?\r
\n" ); document.write( "\n" ); document.write( "Let the width be x\r
\n" ); document.write( "\n" ); document.write( "twice the width = 2x\r
\n" ); document.write( "\n" ); document.write( "length is 4cms less than twice the width
\n" ); document.write( " so length = 2x-4\r
\n" ); document.write( "\n" ); document.write( "Perimeter of rectangle -= 2*( length + width)
\n" ); document.write( "= 2 * ( x+ 2x -4)
\n" ); document.write( "=2*(3x-4)
\n" ); document.write( "= 6x-8\r
\n" ); document.write( "\n" ); document.write( "6x-8 = 40
\n" ); document.write( "6x= 40+8=48
\n" ); document.write( "x=8\r
\n" ); document.write( "\n" ); document.write( "2x-4 = width
\n" ); document.write( "2*8-4=12\r
\n" ); document.write( "\n" ); document.write( "width 8, length 12\r
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