document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260617>Question 260617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Josh can deliver his newspapers in 30 minutes. If Amber helps him, it takes 12 minutes working together. How long would it take amber working by herself? I think that the minutes have to be put into a fraction of the number over 60 but i am not sure.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191983 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Josh can deliver his newspapers in 30 minutes. If Amber helps him, it takes 12 minutes working together. How long would it take amber working by herself?<BR>\n" );
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document.write( "Let x = minutes it takes Amber to deliver by herself<BR>\n" );
document.write( "then<BR>\n" );
document.write( "12(1/30 + 1/x) = 1<BR>\n" );
document.write( "Multiply both sides by 30x:<BR>\n" );
document.write( "12(x + 30) = 30x<BR>\n" );
document.write( "12x + 360 = 30x<BR>\n" );
document.write( "360 = 18x<BR>\n" );
document.write( "360/18 = x<BR>\n" );
document.write( "20 minutes = x<BR>\n" );
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