document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260580>Question 260580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two girls are walking to school.  One is 1250 meters from school and traveling at 70meters per minute and the other girl is 850 meters from school and travels at 40 meters per minute and they leave at the same time when if ever will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191968 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You didn't tell us their route to school! They might meet at school and then again maybe not. We don't even know if they go to the same school.<BR>\n" );
document.write( "a's<BR>\n" );
document.write( "1250=70x<BR>\n" );
document.write( "125/7=17.8571 minutes<BR>\n" );
document.write( "b's<BR>\n" );
document.write( "850=40x<BR>\n" );
document.write( "85/4=21.25 minutes\r<BR>\n" );
document.write( "\n" );
document.write( "70x=40x+400<BR>\n" );
document.write( "x=13 minutes 20 seconds they meet.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );