document.write( "Question 32754: How would you solve the following using the quadratic formula - showing step by step? I know the book says the answer is 2 +- sqrt(2) /2.\r
\n" ); document.write( "\n" ); document.write( "However, I can't seem to come up with that. Here is the problem:
\n" ); document.write( "(3y-1)(2y-3)=y
\n" ); document.write( " Here's what I have so far:
\n" ); document.write( " $\"+6y%5E2-11y%2B3+=+y+\"$
\n" ); document.write( " $\"+6y%5E2-12y%2B3+=+0+\"$
\n" ); document.write( "= -(-12) +- sqrt((-12)^2 -4(6)(3) / 2(6)
\n" ); document.write( "= 12 +- sqrt(144-72) / 12
\n" ); document.write( "= 12 +- sqrt(72) / 12
\n" ); document.write( "= 12+- sqrt(36 *2) / 12
\n" ); document.write( "= 12 +- 6 sqrt(2) / 12
\n" ); document.write( "then what would follow? Thank you. \n" ); document.write( "

Algebra.Com's Answer #19194 by mukhopadhyay(490) $\"\"$ $\"About$

You can put this solution on YOUR website!
= [12 +- 6 sqrt(2)] / 12
\n" ); document.write( "= 1 +- Sqrt(2)/12
\n" ); document.write( "The roots of the equation are: 1 + sqrt(2)/12 and 1 - sqrt(2)/12
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