document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260550>Question 260550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right triangle is 26 cm. the sum of the two other sides is 34 cm. find the lengths of the other two sides of the triangle. how do i solve this ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191920 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the hypotenuse of a right triangle is 26 cm. the sum of the two other sides is 34 cm. find the lengths of the other two sides of the triangle.<BR>\n" );
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document.write( "let one side be x<BR>\n" );
document.write( "The other side is 34-x<BR>\n" );
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document.write( "Pythagoras:<BR>\n" );
document.write( "x^2 + (34-x)^2 = 26^2<BR>\n" );
document.write( "x^2 + 1156  - 68x + x^2 = 676<BR>\n" );
document.write( "2x^2 -68x + 480 = 0<BR>\n" );
document.write( "x^2 - 34x + 240 = 0<BR>\n" );
document.write( "(x-24)(x-10) = 0<BR>\n" );
document.write( "x = 24 or x = 10<BR>\n" );
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document.write( "One side is 10 cm the other is 24 cm.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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