document.write( "Question 260559: Could you help solve the quadratic equatin by completing the square
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document.write( "2x^2 - 6x + 5
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document.write( "Thank You,
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document.write( "Stacie Rihl \n" );
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Algebra.Com's Answer #191918 by onlinetutor365.com(14)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "2(x2) - 6x + 5 = 0\r \n" ); document.write( "\n" ); document.write( "Solving for variable 'x'.\r \n" ); document.write( "\n" ); document.write( "Begin completing the square. Divide all terms by 2 the coefficient of the squared term: \r \n" ); document.write( "\n" ); document.write( "Divide each side by '2'. \n" ); document.write( "x^2 - 3x + 2.5 = 0\r \n" ); document.write( "\n" ); document.write( "Move the constant term to the right:\r \n" ); document.write( "\n" ); document.write( "Add '-2.5' to each side of the equation. \n" ); document.write( "x^2-3x +2.5 -2.5=-2.5\r \n" ); document.write( "\n" ); document.write( "x^2 -3x =-2.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The x term is -3x. Take half its coefficient (-1.5). \n" ); document.write( "Square it (2.25) and add it to both sides.\r \n" ); document.write( "\n" ); document.write( "Add '2.25' to each side of the equation. \n" ); document.write( "x2-3x + 2.25 = -2.5 + 2.25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x2-3x + 2.25= -0.25\r \n" ); document.write( "\n" ); document.write( "Factor a perfect square on the left side: \n" ); document.write( "(x -1.5)(x -1.5) = -0.25\r \n" ); document.write( "\n" ); document.write( "Can't calculate square root of the right side.\r \n" ); document.write( "\n" ); document.write( "The solution to this equation could not be determined.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |