document.write( "Question 260512: 10-log(5,2x-9)=9 \n" ); document.write( "
Algebra.Com's Answer #191898 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
here is the original problem
\n" ); document.write( "\"10-log%285%2C2x-9%29=9\"
\n" ); document.write( "step 1 - subtract 10 to get
\n" ); document.write( "\"-log%285%2C2x-9%29+=+-1\"
\n" ); document.write( "divide by -1 to get
\n" ); document.write( "\"log%285%2C2x-9%29+=+1\"
\n" ); document.write( "rewrite as powers to get
\n" ); document.write( " \"5%5E1+=+2x-9\"
\n" ); document.write( "solve for x to get
\n" ); document.write( "\"x+=+7\"
\n" ); document.write( "
\n" );