document.write( "Question 260516: log(3x)= log 5 + log(x-2) \n" ); document.write( "

Algebra.Com's Answer #191891 by drk(1908) $\"\"$ $\"About$

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Here is the question
\n" ); document.write( " $\"log%283x%29=+log+5+%2B+log%28x-2%29\"$
\n" ); document.write( "step 1 subtract log(x-2) to get
\n" ); document.write( " $\"log%283x%29+-+log%28x-2%29+=+log%285%29\"$
\n" ); document.write( "step 2 - rewrite using rules of logs as
\n" ); document.write( " $\"log%283x%2F%28x-2%29%29+=+log%285%29\"$
\n" ); document.write( "step 3 - eliminate logs to get
\n" ); document.write( " $\"3x%2F%28x-2%29+=+5\"$
\n" ); document.write( "step 4 - cross multiply to get
\n" ); document.write( " $\"3x+=+5x+-+10\"$
\n" ); document.write( "solve for x and we get
\n" ); document.write( "x = 5 \n" ); document.write( "

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