document.write( "Question 260505: 1100/1+99e^-.3t=275 \n" ); document.write( "
Algebra.Com's Answer #191886 by drk(1908) ![]() You can put this solution on YOUR website! The original question is \n" ); document.write( "(i) \n" ); document.write( "step 1 - cross multiply to get \n" ); document.write( "(ii) \n" ); document.write( "step 2 - divide by 275 to get \n" ); document.write( "(iii) \n" ); document.write( "step 3 - subtract 1 to get \n" ); document.write( "(iv) \n" ); document.write( "step 4 - divide by 99 to get \n" ); document.write( "(v) \n" ); document.write( "apply ln to both sdies to get \n" ); document.write( "(vi) \n" ); document.write( "multiply by -1/.3 to get \n" ); document.write( "(vii) \n" ); document.write( "So, \n" ); document.write( " |