document.write( "Question 260505: 1100/1+99e^-.3t=275 \n" ); document.write( "
Algebra.Com's Answer #191886 by drk(1908)\"\" \"About 
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The original question is
\n" ); document.write( "(i) \"1100%2F%281%2B99e%5E%28-.3t%29%29=275\"
\n" ); document.write( "step 1 - cross multiply to get
\n" ); document.write( "(ii) \"1100+=+275%2A%281%2B99e%5E%28-.3t%29%29\"
\n" ); document.write( "step 2 - divide by 275 to get
\n" ); document.write( "(iii) \"4+=+1+%2B+99e%5E%28-.3t%29\"
\n" ); document.write( "step 3 - subtract 1 to get
\n" ); document.write( "(iv) \"3+=+99e%5E%28-.3t%29\"
\n" ); document.write( "step 4 - divide by 99 to get
\n" ); document.write( "(v) \"%281%2F33%29+=+e%5E%28-.3t%29\"
\n" ); document.write( "apply ln to both sdies to get
\n" ); document.write( "(vi) \"ln%281%2F33%29+=+-.3t\"
\n" ); document.write( "multiply by -1/.3 to get
\n" ); document.write( "(vii) \"%28-1%2F.3%29%2Aln%281%2F33%29+=+t\"
\n" ); document.write( "So,
\n" ); document.write( "\"t+=+11.655\"
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