document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260483>Question 260483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191881 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "3A = 2B<BR>\n" );
document.write( "2A = B + 3<BR>\n" );
document.write( "-----------------------------<BR>\n" );
document.write( "Rearrange:<BR>\n" );
document.write( "B = 2A - 3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Substitute for \"B\" and solve for \"A\":<BR>\n" );
document.write( "3A = 2(2A-3)<BR>\n" );
document.write( "3A = 4A - 6<BR>\n" );
document.write( "A = 6 (1st number)<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Since B = 2A-3, B = 2*6-3 = 9 (2nd number)<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );