document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260483>Question 260483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191877 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers\r<BR>\n" );
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document.write( "Let x be the first and y the second number.\r<BR>\n" );
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document.write( "Then we have:\r<BR>\n" );
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document.write( "1.) 3*x = 2*y<BR>\n" );
document.write( "2.) 2*x = y + 3\r<BR>\n" );
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document.write( "Solve by substitution:<BR>\n" );
document.write( "From 2.) we know that y = 2*x - 3\r<BR>\n" );
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document.write( "Substitute 2x - 3 for y in equation 1.)\r<BR>\n" );
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document.write( "3x = 2*(2x-3)\r<BR>\n" );
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document.write( "Solve the above for x. Then calculate y = 2x - 3.  </SPAN>\n" );
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