document.write( "Question 260483: three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers \n" ); document.write( "

Algebra.Com's Answer #191868 by drk(1908) $\"\"$ $\"About$

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Let A be the first number and B be the second number
\n" ); document.write( "three times one number equals twice a second number
\n" ); document.write( " translates as
\n" ); document.write( "(i) $\"3A+=+2B\"$
\n" ); document.write( "twice the first number is 3 more than the second number
\n" ); document.write( "translates as
\n" ); document.write( "(ii) $\"2A+=+B+%2B+3\"$
\n" ); document.write( "solve (ii) for B to get
\n" ); document.write( "(iii) $\"B+=+2A+-+3\"$
\n" ); document.write( "substitute (ii) into (i) to get
\n" ); document.write( "(iv) $\"3A+=+2%282A-3%29\"$
\n" ); document.write( "distribute to get
\n" ); document.write( "(v) $\"3A+=+4A+-+6\"$
\n" ); document.write( "subtract 4A to get
\n" ); document.write( "(vi) $\"-A+=+-6\"$
\n" ); document.write( "divide by -1 to get
\n" ); document.write( "(vii) $\"A+=+6\"$
\n" ); document.write( "since A = 6, $\"B+=+9\"$ \n" ); document.write( "

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