document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260475>Question 260475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat travels 60 km upstream (against the current) in 5 hours. The boat travels the same distance downstream in 3 hours. What is the rate of the boat in still water? What is the rate of the current?\r<BR>\n" );
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document.write( "I need to use a system of 2 equations in 2 variables in the answer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191853 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "60=R*5<BR>\n" );
document.write( "R=60/5<BR>\n" );
document.write( "R=12 KMH. GOING UPSTREAM.<BR>\n" );
document.write( "60=R*3<BR>\n" );
document.write( "R=60/3<BR>\n" );
document.write( "R=20 KMH. GOING DOWNSTREAM.<BR>\n" );
document.write( "(20-12)/2=8/2=4 KMH IS THE CURRENT SPEED.<BR>\n" );
document.write( "12+4=16 KMH IS THE BOAT SPEED<BR>\n" );
document.write( "20-4=16 DITTO.<BR>\n" );
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