document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32728>Question 32728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can not figure out the last steps on how the answer is attain<BR>\n" );
document.write( "Please help show each step also how to enter it in the calculator for graphing solution.\r<BR>\n" );
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document.write( "3^(2x+2) =7^X<BR>\n" );
document.write( "ln (3^2x+2) ==ln 7^x<BR>\n" );
document.write( "(2x+2) ln (3) = x ln(7)<BR>\n" );
document.write( "2x ln (3)= x ln 7-2 ln 3<BR>\n" );
document.write( "2x ln (30-x(7)==-2 ln(3)<BR>\n" );
document.write( "x(2 ln 3-ln 7) = -2 ln (3)<BR>\n" );
document.write( "x=<BR>\n" );
document.write( "Now I am stuck how do I finish it????  How is it enter into the calculator. Must know for my math class.<BR>\n" );
document.write( "Any help, very appreciated.<BR>\n" );
document.write( "thanks,<BR>\n" );
document.write( "Jody </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19183 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^(2x+2) = 7^X<BR>\n" );
document.write( "ln (3^2x+2) =ln 7^x<BR>\n" );
document.write( "(2x+2) ln (3) = x ln(7)<BR>\n" );
document.write( "2x ln (3)-x ln 7 = -2 ln 3<BR>\n" );
document.write( "x[2 ln (3) - ln (7)] = -2 ln(3)<BR>\n" );
document.write( "x = [2 ln (3) - ln (7) ]/ [-2 ln(3)]\r<BR>\n" );
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document.write( "x= ln (7)/[2 ln (3)] - 1<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );