document.write( "Question 260357: The ratio of Aldo's cycling speed to Jose cycling speed is 6:5. Jose leaves school at 3pm and Aldo leaves at 3:10pm. By 3:30pm Aldo is only 2km behind Jose. How fast is each cycling? \n" ); document.write( "
Algebra.Com's Answer #191791 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! The ratio of Aldo's cycling speed to Jose cycling speed is 6:5. \n" ); document.write( " Jose leaves school at 3pm and Aldo leaves at 3:10pm. \n" ); document.write( " By 3:30pm Aldo is only 2km behind Jose. How fast is each cycling? \n" ); document.write( ": \n" ); document.write( "Let x = the multiplier \n" ); document.write( "then \n" ); document.write( "6x = A's speed \n" ); document.write( "and \n" ); document.write( "5x = J's speed \n" ); document.write( ": \n" ); document.write( "At 3:30 \n" ); document.write( "30 min = J's travel time, which is \n" ); document.write( "20 min = A's travel time, which is \n" ); document.write( ": \n" ); document.write( "Write a distance equation: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "J's dist - A's dist = 2 km \n" ); document.write( " \n" ); document.write( "Multiply equation by 6 to get rid of the denominators, results \n" ); document.write( "3(5x) - 2(6x) = 6(2) \n" ); document.write( ": \n" ); document.write( "15x - 12x = 12 \n" ); document.write( ": \n" ); document.write( "3x = 12 \n" ); document.write( "x = \n" ); document.write( "x = 4 is the multiplier \n" ); document.write( ": \n" ); document.write( "6*4 = 24 km/hr is A's speed \n" ); document.write( "5*4 = 20 km/hr is J's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the distance each traveled \n" ); document.write( "A: \n" ); document.write( "J: \n" ); document.write( " \n" ); document.write( " |