document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32644>Question 32644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> show the steps to simplify the first expression to the second expression:\r<BR>\n" );
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document.write( "I'll let theta be equal to x.\r<BR>\n" );
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document.write( "csc^2x - cot^2x/1+tan^2x , cos^2x\r<BR>\n" );
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document.write( "thanks so much to whomever can help me with this!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19179 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (csc^2x - cot^2x)/(1+tan^2x)<BR>\n" );
document.write( "=1/SEC^2 X...SINCE COSEC^2 X - COT^2 X=1..AND 1+TAN^2 X = SEC^2 X<BR>\n" );
document.write( "=COS^2 X </SPAN>\n" );
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