document.write( "Question 32695:  3
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document.write( "y^2-3y+2     \r
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document.write( "7
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document.write( "y^2-1 \n" );
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| Algebra.Com's Answer #19176 by mukhopadhyay(490)      You can put this solution on YOUR website! [3/(y^2-3y+2)] + 7/(y^2-1) \n" ); document.write( "= [3/(y-2)(y-1)] + 7/(y-1)(y+1) \n" ); document.write( "= [3(y+1) + 7(y-2)]/(y-1)(y+1)(y-2) \n" ); document.write( "= (10y-11)/(y-1)(y+1)(y-2) \n" ); document.write( " \n" ); document.write( " |