document.write( "Question 32695: 3
\n" ); document.write( "___
\n" ); document.write( "y^2-3y+2 \r
\n" ); document.write( "\n" ); document.write( "Plus\r
\n" ); document.write( "\n" ); document.write( "7
\n" ); document.write( "____
\n" ); document.write( "y^2-1
\n" ); document.write( "

Algebra.Com's Answer #19176 by mukhopadhyay(490)\"\" \"About 
You can put this solution on YOUR website!
[3/(y^2-3y+2)] + 7/(y^2-1)
\n" ); document.write( "= [3/(y-2)(y-1)] + 7/(y-1)(y+1)
\n" ); document.write( "= [3(y+1) + 7(y-2)]/(y-1)(y+1)(y-2)
\n" ); document.write( "= (10y-11)/(y-1)(y+1)(y-2)
\n" ); document.write( "
\n" ); document.write( "
\n" );