document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260303>Question 260303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay. So how do you find the area of a semi-circle if you already have the perimeter? I am solving a problem where the perimeter is 20 and it wants me to find the area of the semi circle. plz help me out!<BR>\n" );
document.write( "Thankss! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191730 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a semi-circle is pi*d/2 + d<BR>\n" );
document.write( "The perimeter has 2 parts: the circular part which is 1/2 the circumference of a circle and a flat part which is the diameter of the circle.<BR>\n" );
document.write( "pi*d/2 + d=20<BR>\n" );
document.write( "pi*d+2d=40<BR>\n" );
document.write( "d(pi+2)=40<BR>\n" );
document.write( "d=40/(pi+2)<BR>\n" );
document.write( "r=20/(pi+2)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "A=(pi*r^2)/2<BR>\n" );
document.write( "=pi*(20/(pi+2))^2/2<BR>\n" );
document.write( "=pi*(400/(pi+2)^2)*1/2<BR>\n" );
document.write( "=200pi/(pi+2)^2 or 23.77<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );