document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=260303>Question 260303</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay. So how do you find the area of a semi-circle if you already have the perimeter? I am solving a problem where the perimeter is 20 and it wants me to find the area of the semi circle. plz help me out!<BR>\n" );
document.write( "Thankss! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #191728 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=191728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lets start with the circumference formula as<BR>\n" );
document.write( "(i) C = 2*pi*r<BR>\n" );
document.write( "and the area formula as<BR>\n" );
document.write( "(ii) A = pi*r^2.<BR>\n" );
document.write( "solve the circumference for pi as<BR>\n" );
document.write( "(iii) pi = C/(2r)<BR>\n" );
document.write( "Now put that into the area formula as<BR>\n" );
document.write( "(iv) A = C/(2r)*r^2<BR>\n" );
document.write( "which is<BR>\n" );
document.write( "(v) A = Cr/2<BR>\n" );
document.write( "From (i) the radius is<BR>\n" );
document.write( "(vi) r = C/(2pi)<BR>\n" );
document.write( "putting (vi) into (v) we get<BR>\n" );
document.write( "(vii) A = C^2/(4pi) - - - This is the formula you want.<BR>\n" );
document.write( "--<BR>\n" );
document.write( "You were given perimeter (circumference) = 20<BR>\n" );
document.write( "So,<BR>\n" );
document.write( "from (vii) we get<BR>\n" );
document.write( "A = 20^2/(4pi) = 400/(4pi) = 100/pi </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );