document.write( "Question 260277: Solve this equation: x^3+729=0\r
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document.write( "I know this much: 1st solution is -9
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document.write( "(x+9)^3=0
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document.write( "(x+9)[x^2-9x+81]\r
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document.write( "This is where I'm stuck..When I use the quadratic formula I get\r
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document.write( "9 +/-square root of 243 over 2\r
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document.write( "Now what? The answer is 9 +9i 'square root' of 3 over 2. How do you get that? \n" );
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Algebra.Com's Answer #191712 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Here is the original question: \n" ); document.write( " \n" ); document.write( "we can express this as the sum of cubes, but first write them both as powers of 3, as \n" ); document.write( " \n" ); document.write( "Now, we get \n" ); document.write( " \n" ); document.write( "next set each part =0 and solve. \n" ); document.write( "x+9 = 0 \n" ); document.write( "x = -9 \n" ); document.write( "-- \n" ); document.write( "x^2-9x+81= 0 \n" ); document.write( "by quadratic, we get \n" ); document.write( " \n" ); document.write( "which simplifies to \n" ); document.write( " \n" ); document.write( "which is \n" ); document.write( " \n" ); document.write( "which will give us imaginary roots as \n" ); document.write( " \n" ); document.write( "-- \n" ); document.write( "we have three roots \n" ); document.write( "x = -9 \n" ); document.write( "x = (9+9isqrt(3))/2 \n" ); document.write( "x = (9-9isqrt(3))/2 \n" ); document.write( " |