document.write( "Question 260277: Solve this equation: x^3+729=0\r
\n" ); document.write( "\n" ); document.write( "I know this much: 1st solution is -9
\n" ); document.write( "(x+9)^3=0
\n" ); document.write( "(x+9)[x^2-9x+81]\r
\n" ); document.write( "\n" ); document.write( "This is where I'm stuck..When I use the quadratic formula I get\r
\n" ); document.write( "\n" ); document.write( "9 +/-square root of 243 over 2\r
\n" ); document.write( "\n" ); document.write( "Now what? The answer is 9 +9i 'square root' of 3 over 2. How do you get that?
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Algebra.Com's Answer #191712 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
Here is the original question:
\n" ); document.write( "\"x%5E3%2B729=0+\"
\n" ); document.write( "we can express this as the sum of cubes, but first write them both as powers of 3, as
\n" ); document.write( "\"x%5E3%2B9%5E3+=+0\"
\n" ); document.write( "Now, we get
\n" ); document.write( "\"%28x%2B9%29%28x%5E2-9x%2B81%29=0\"
\n" ); document.write( "next set each part =0 and solve.
\n" ); document.write( "x+9 = 0
\n" ); document.write( "x = -9
\n" ); document.write( "--
\n" ); document.write( "x^2-9x+81= 0
\n" ); document.write( "by quadratic, we get
\n" ); document.write( "\"x+=+%289+%2B-+sqrt%28+81-4%2A1%2A81+%29%29%2F%282%29+\"
\n" ); document.write( "which simplifies to
\n" ); document.write( "\"x+=+%289+%2B-+sqrt%2881-324%29%29%2F%282%29+\"
\n" ); document.write( "which is
\n" ); document.write( "\"x+=+%289+%2B-+sqrt%28-243+%29%29%2F%282%29+\"
\n" ); document.write( "which will give us imaginary roots as
\n" ); document.write( "\"x+=+%289+%2B-+9%2Aisqrt%283%29%29%2F2\"
\n" ); document.write( "--
\n" ); document.write( "we have three roots
\n" ); document.write( "x = -9
\n" ); document.write( "x = (9+9isqrt(3))/2
\n" ); document.write( "x = (9-9isqrt(3))/2
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