document.write( "Question 260211: The sum of the digits of a two-digit number is 14. If the digits are reversed, the number is 18 less than the original number. Find the original number. \n" ); document.write( "
Algebra.Com's Answer #191705 by ankor@dixie-net.com(22740)\"\" \"About 
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Let x = the 10's digit
\n" ); document.write( "Let y = the units
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\n" ); document.write( "10x + y = the original two digit number
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\n" ); document.write( "The sum of the digits of a two-digit number is 14.
\n" ); document.write( "x + y = 14
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\n" ); document.write( "\"If the digits are reversed, the number is 18 less than the original number.\"
\n" ); document.write( "Rev no. = orig no. - 18
\n" ); document.write( "10y + x = 10x + y - 18
\n" ); document.write( "10y - y = 10x - x - 18
\n" ); document.write( "9y = 9x - 18
\n" ); document.write( "simplify, divide by 9
\n" ); document.write( "y = x - 2
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\n" ); document.write( "In the sum equation replace y with (x-2)
\n" ); document.write( "x + (x-2) = 14
\n" ); document.write( "2x = 14 + 2
\n" ); document.write( "2x = 16
\n" ); document.write( "x = 8
\n" ); document.write( "obviously y = 6
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\n" ); document.write( "86 is the original number
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"If the digits are reversed, the number is 18 less than the original number.\"
\n" ); document.write( "68 = 86 - 18\r
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