document.write( "Question 260252: An airline claims that the no-show rate for passengers is less than 5%. In a sample of 420 randomly selected reservations, 19 were no-shows. Use a level of significance of = 0.01 to test the airlines claim. (Round phat to 4 decimal places.)
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document.write( "(References: examples 1 through 3 pages 408 - 410, end of section exercises 9 - 14 pages 411 - 412) (6 points)\r
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document.write( "1. H0 :
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document.write( "Ha :
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document.write( "2. =
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document.write( "3. Test statistics:
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document.write( "4. P-value or critical z0 or t0.
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document.write( "5. Rejection Region:
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document.write( "6. Decision:
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document.write( "7. Interpretation:
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Algebra.Com's Answer #191690 by stanbon(75887) ![]() You can put this solution on YOUR website! An airline claims that the no-show rate for passengers is less than 5%. In a sample of 420 randomly selected reservations, 19 were no-shows. Use a level of significance of = 0.01 to test the airlines claim. (Round phat to 4 decimal places.) \n" ); document.write( "(References: examples 1 through 3 pages 408 - 410, end of section exercises 9 - 14 pages 411 - 412) (6 points) \r \n" ); document.write( "\n" ); document.write( "1. \n" ); document.write( "H0 : p >= 0.05 \n" ); document.write( "Ha : p < 0.05 (airline claim) \n" ); document.write( "------------------------------------- \n" ); document.write( "2. = 1% \n" ); document.write( "3. Test statistics: \n" ); document.write( "z(19/420) = (0.0452 - 0.05)= 0.0048/sqrt[0.05*0.95/420] = -0.4514 \n" ); document.write( "--- \n" ); document.write( "4. P-value or critical z0 or t0. \n" ); document.write( "p-value = P(z< -0.4478) = normalcdf(-100,-0.4514) = 0.3259.. \n" ); document.write( "---------------------------- \n" ); document.write( "5. Rejection Region: \n" ); document.write( "cv = invNorm(0.01) = -2.326.. \n" ); document.write( "Reject Ho if ts < -2.326 \n" ); document.write( "-------------------------------- \n" ); document.write( "6. Decision: Since the p-value is greater than 1%, fail to reject Ho. \n" ); document.write( "------ \n" ); document.write( "7. Interpretation: \n" ); document.write( "The proportion of no-shows is greater than or equal to 5% at \n" ); document.write( "a 1% significance level. These test results support denying \n" ); document.write( "the airline's claim. \n" ); document.write( "============================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |